How do I use sys.exit()?
How do I use sys.exit() in this while loop?
The user inputs 3 sides of a triangle. If it is a right angle Pythagorean triangle, then it prints.
If the user enters "0", the program ends.
Also, is there a better way to write the infinite while loop besides using count = 0 and never incrementing it?
def pythagoreanTriple():
count = 0
print("input 3 sides of a triangle")
print("or enter 0 to quit")
while count < 1:
sides = []
for i in range(0, 3):
side = int(input("Input a side: "))
sides.append(side)
sides = sorted(sides)
if sides[0] ** 2 + sides[1] ** 2 == sides[2] ** 2:
print('That is a Pythagorean Triple!')
else:
print('That is not a Pythagorean Triple...')
else:
sys.exit(0)
pythagoreanTriple()
Asked by: Richard530 | Posted: 27-01-2022
Answer 1
You could wrap the snippet in an infinite loop and break only if the cond. is met:
def pythagoreanTriple():
while True:
userInp = input("Enter 1 to continue 0 to exit: ")
if userInp.lower() == "0":
break
sides = []
for i in range(0, 3):
side = int(input("Input a side: "))
sides.append(side)
sides = sorted(sides)
if sides[0] ** 2 + sides[1] ** 2 == sides[2] ** 2:
print('That is a Pythagorean Triple!')
else:
print('That is not a Pythagorean Triple...')
pythagoreanTriple()
OUTPUT:
Enter 1 to continue 0 to exit: 1
Input a side: 5
Input a side: 5
Input a side: 10
That is not a Pythagorean Triple...
Enter 1 to continue 0 to exit: 0
Process finished with exit code 0
Answer 2
You need to put your sys.exit() inside your while loop, or it will never stop.
Moreover, in order to have an infinite loop, mostly people use while True.
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