How to skip sys.exitfunc when unhandled exceptions occur
As you can see, even after the program should have died it speaks from the grave. Is there a way to "deregister" the exitfunction in case of exceptions?
import atexit def helloworld(): print("Hello World!") atexit.register(helloworld) raise Exception("Good bye cruel world!")
Traceback (most recent call last): File "test.py", line 8, in <module> raise Exception("Good bye cruel world!") Exception: Good bye cruel world! Hello World!
Asked by: John406 | Posted: 28-01-2022
I don't really know why you want to do that, but you can install an excepthook that will be called by Python whenever an uncatched exception is raised, and in it clear the array of registered function in the
Something like that :
import sys import atexit def clear_atexit_excepthook(exctype, value, traceback): atexit._exithandlers[:] =  sys.__excepthook__(exctype, value, traceback) def helloworld(): print "Hello world!" sys.excepthook = clear_atexit_excepthook atexit.register(helloworld) raise Exception("Good bye cruel world!")
Beware that it may behave incorrectly if the exception is raised from an
atexit registered function (but then the behaviour would have been strange even if this hook was not used).
In addition to calling os._exit() to avoid the registered exit handler you also need to catch the unhandled exception:
Answered by: Kevin875 | Posted: 01-03-2022
import atexit import os def helloworld(): print "Hello World!" atexit.register(helloworld) try: raise Exception("Good bye cruel world!") except Exception, e: print 'caught unhandled exception', str(e) os._exit(1)
If you call
import os os._exit(0)
the exit handlers will not be called, yours or those registered by other modules in the application.Answered by: Elise583 | Posted: 01-03-2022
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