# Calculate time between time-1 to time-2?

```
enter time-1 // eg 01:12
enter time-2 // eg 18:59
calculate: time-1 to time-2 / 12
// i.e time between 01:12 to 18:59 divided by 12
```

How can it be done in Python. I'm a beginner so I really have no clue where to start.

Edited to add: I don't want a timer. Both time-1 and time-2 are entered by the user manually.

Thanks in advance for your help.

Asked by:

**Richard477**| Posted: 06-12-2021

# Answer 1

The `datetime`

and `timedelta`

class from the built-in `datetime`

module is what you need.

```
from datetime import datetime
# Parse the time strings
t1 = datetime.strptime('01:12','%H:%M')
t2 = datetime.strptime('18:59','%H:%M')
# Do the math, the result is a timedelta object
delta = (t2 - t1) / 12
print(delta.seconds)
```

Answered by: **Miranda906**| Posted: 07-01-2022

# Answer 2

Simplest and most direct may be something like:

```
def getime(prom):
"""Prompt for input, return minutes since midnight"""
s = raw_input('Enter time-%s (hh:mm): ' % prom)
sh, sm = s.split(':')
return int(sm) + 60 * int(sh)
time1 = getime('1')
time2 = getime('2')
diff = time2 - time1
print "Difference: %d hours and %d minutes" % (diff//60, diff%60)
```

E.g., a typical run might be:

```
$ python ti.py
Enter time-1 (hh:mm): 01:12
Enter time-2 (hh:mm): 18:59
Difference: 17 hours and 47 minutes
```

Answered by: **Maria751**| Posted: 07-01-2022

# Answer 3

Here's a timer for timing code execution. Maybe you can use it for what you want. time() returns the current time in seconds and microseconds since 1970-01-01 00:00:00.

```
from time import time
t0 = time()
# do stuff that takes time
print time() - t0
```

Answered by: **Max587**| Posted: 07-01-2022

# Answer 4

Assuming that the user is entering strings like `"01:12"`

, you need to convert (as well as validate) those strings into the number of minutes since `00:00`

(e.g., `"01:12"`

is `1*60+12`

, or 72 minutes), then subtract one from the other. You can then convert the difference in minutes back into a string of the form `hh:mm`

.

**John689**| Posted: 07-01-2022

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