Make dictionary from list with python [duplicate]
I need to transform a list into dictionary as follows. The odd elements has the key, and even number elements has the value.
x = (1,'a',2,'b',3,'c') -> {1: 'a', 2: 'b', 3: 'c'}
def set(self, val_):
i = 0
for val in val_:
if i == 0:
i = 1
key = val
else:
i = 0
self.dict[key] = val
A better way to get the same results?
ADDED
i = iter(k)
print dict(zip(i,i))
seems to be working
Asked by: Roland104 | Posted: 27-01-2022
Answer 1
dict(x[i:i+2] for i in range(0, len(x), 2))
Answer 2
Here are a couple of ways for Python3 using dict comprehensions
>>> x = (1,'a',2,'b',3,'c')
>>> {k:v for k,v in zip(*[iter(x)]*2)}
{1: 'a', 2: 'b', 3: 'c'}
>>> {x[i]:x[i+1] for i in range(0,len(x),2)}
{1: 'a', 2: 'b', 3: 'c'}
Answer 3
dict(zip(*[iter(val_)] * 2))
Answer 4
>>> x=(1,'a',2,'b',3,'c')
>>> dict(zip(x[::2],x[1::2]))
{1: 'a', 2: 'b', 3: 'c'}
Answer 5
x = (1,'a',2,'b',3,'c')
d = dict(x[n:n+2] for n in xrange(0, len(x), 2))
print d
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