What is the simplest way to find the difference between 2 times in python?
I have 2 time values which have the type
datetime.time. I want to find their difference. The obvious thing to do is t1 - t2, but this doesn't work. It works for objects of type
datetime.datetime but not for
datetime.time. So what is the best way to do this?
Asked by: Aida311 | Posted: 28-01-2022
Also a little silly, but you could try picking an arbitrary day and embedding each time in it, using
datetime.datetime.combine, then subtracting:
Answered by: Emma575 | Posted: 01-03-2022
>>> import datetime >>> t1 = datetime.time(2,3,4) >>> t2 = datetime.time(18,20,59) >>> dummydate = datetime.date(2000,1,1) >>> datetime.datetime.combine(dummydate,t2) - datetime.datetime.combine(dummydate,t1) datetime.timedelta(0, 58675)
You could transform both into timedelta objects and subtract these from each other, which will take care to of the carry-overs. For example:
>>> import datetime as dt >>> t1 = dt.time(23, 5, 5, 5) >>> t2 = dt.time(10, 5, 5, 5) >>> dt1 = dt.timedelta(hours=t1.hour, minutes=t1.minute, seconds=t1.second, microseconds=t1.microsecond) >>> dt2 = dt.timedelta(hours=t2.hour, minutes=t2.minute, seconds=t2.second, microseconds=t2.microsecond) >>> print(dt1-dt2) 13:00:00 >>> print(dt2-dt1) -1 day, 11:00:00 >>> print(abs(dt2-dt1)) 13:00:00
Negative timedelta objects in Python get a negative day field, with the other fields positive. You could check beforehand: comparison works on both time objects and timedelta objects:
Answered by: Marcus513 | Posted: 01-03-2022
>>> dt2 < dt1 True >>> t2 < t1 True
Python has pytz (http://pytz.sourceforge.net) module which can be used for arithmetic of 'time' objects. It takes care of DST offsets as well. The above page has a number of examples that illustrate the usage of pytz.Answered by: Ada119 | Posted: 01-03-2022
It seems that this isn't supported, since there wouldn't be a good way to deal with overflows in datetime.time. I know this isn't an answer directly, but maybe someone with more python experience than me can take this a little further. For more info, see this: http://bugs.python.org/issue3250Answered by: Roland395 | Posted: 01-03-2022
Firstly, note that a datetime.time is a time of day, independent of a given day, and so the different between any two datetime.time values is going to be less than 24 hours.
One approach is to convert both datetime.time values into comparable values (such as milliseconds), and find the difference.
t1, t2 = datetime.time(...), datetime.time(...) t1_ms = (t1.hour*60*60 + t1.minute*60 + t1.second)*1000 + t1.microsecond t2_ms = (t2.hour*60*60 + t2.minute*60 + t2.second)*1000 + t2.microsecond delta_ms = max([t1_ms, t2_ms]) - min([t1_ms, t2_ms])
It's a little lame, but it works.Answered by: Maddie247 | Posted: 01-03-2022
Retrieve the times in milliseconds and then do the subtraction.Answered by: Rebecca202 | Posted: 01-03-2022
Environment.TickCount seems to work well if you need something quick.
int start = Environment.TickCount
int elapsedtime = Environment.TickCount - start
JonAnswered by: Samantha260 | Posted: 01-03-2022
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