# Parsing numbers in Python

i want to take inputs like this 10 12

13 14

15 16

..

how to take this input , as two diffrent integers so that i can multiply them in python after every 10 and 12 there is newline

Asked by: Luke508 | Posted: 06-12-2021

I'm not sure I understood your problem very well, it seems you want to parse two int separated from a space.

In python you do:

s = raw_input('Insert 2 integers separated by a space: ')
a,b = [int(i) for i in s.split(' ')]
print a*b


Explanation:

s = raw_input('Insert 2 integers separated by a space: ')


raw_input takes everything you type (until you press enter) and returns it as a string, so:

>>> raw_input('Insert 2 integers separated by a space: ')
Insert 2 integers separated by a space: 10 12
'10 12'


In s you have now '10 12', the two int are separated by a space, we split the string at the space with

>>> s.split(' ')
['10', '12']


now you have a list of strings, you want to convert them in int, so:

>>> [int(i) for i in s.split(' ')]
[10, 12]


then you assign each member of the list to a variable (a and b) and then you do the product a*b

Answered by: Kellan739 | Posted: 07-01-2022

f = open('inputfile.txt')
# the next line is equivalent to:
# s1, s2 = line.split(' ')
# a = int(s1)
# b = int(s2)
a, b = map(int, line.split(' '))
print a*b


Answered by: David623 | Posted: 07-01-2022

You could use regular expressions (re-module)

import re

test = "10 11\n12 13" # Get this input from the files or the console

matches = re.findall(r"(\d+)\s*(\d+)", test)
products = [ int(a) * int(b)  for a, b in matches ]

# Process data
print(products)


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