Python: can I have a list with named indices?
In PHP I can name my array indices so that I may have something like:
$shows = Array(0 => Array('id' => 1, 'name' => 'Sesame Street'),
1 => Array('id' => 2, 'name' => 'Dora The Explorer'));
Is this possible in Python?
Asked by: Walter823 | Posted: 28-01-2022
Answer 1
This sounds like the PHP array using named indices is very similar to a python dict:
shows = [
{"id": 1, "name": "Sesaeme Street"},
{"id": 2, "name": "Dora The Explorer"},
]
See http://docs.python.org/tutorial/datastructures.html#dictionaries for more on this.
Answered by: Kelvin359 | Posted: 01-03-2022Answer 2
PHP arrays are actually maps, which is equivalent to dicts in Python.
Thus, this is the Python equivalent:
showlist = [{'id':1, 'name':'Sesaeme Street'}, {'id':2, 'name':'Dora the Explorer'}]
Sorting example:
from operator import attrgetter
showlist.sort(key=attrgetter('id'))
BUT! With the example you provided, a simpler datastructure would be better:
shows = {1: 'Sesame Street', 2:'Dora the Explorer'}
Answer 3
@Unkwntech,
What you want is available in the just-released Python 2.6 in the form of named tuples. They allow you to do this:
import collections
person = collections.namedtuple('Person', 'id name age')
me = person(id=1, age=1e15, name='Dan')
you = person(2, 'Somebody', 31.4159)
assert me.age == me[2] # can access fields by either name or position
Answer 4
Yes,
a = {"id": 1, "name":"Sesame Street"}
Answer 5
The pandas library has a really neat solution: Series.
book = pandas.Series( ['Introduction to python', 'Someone', 359, 10],
index=['Title', 'Author', 'Number of pages', 'Price'])
print book['Author']
For more information check it's documentation: http://pandas.pydata.org/pandas-docs/stable/generated/pandas.Series.html.
Answered by: Aida395 | Posted: 01-03-2022Answer 6
I think what you are asking is about python dictionaries.There you can named your indices as you wish . For ex:
dictionary = {"name": "python", "age": 12}
Answer 7
Python has lists and dicts as 2 separate data structures. PHP mixes both into one. You should use dicts in this case.
Answered by: Chester968 | Posted: 01-03-2022Answer 8
I did it like this:
def MyStruct(item1=0, item2=0, item3=0):
"""Return a new Position tuple."""
class MyStruct(tuple):
@property
def item1(self):
return self[0]
@property
def item2(self):
return self[1]
@property
def item3(self):
return self[2]
try:
# case where first argument a 3-tuple
return MyStruct(item1)
except:
return MyStruct((item1, item2, item3))
I did it also a bit more complicate with list instead of tuple, but I had override the setter as well as the getter.
Anyways this allows:
a = MyStruct(1,2,3)
print a[0]==a.item1
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