Python script to list users and groups
I'm attempting to code a script that outputs each user and their group on their own line like so:
user1 group1 user2 group1 user3 group2 ... user10 group6
I'm writing up a script in python for this but was wondering how SO might do this.
p.s. Take a whack at it in any language but I'd prefer python.
EDIT: I'm working on Linux. Ubuntu 8.10 or CentOS =)
Asked by: Cadie831 | Posted: 24-09-2021
Answered by: Cadie948 | Posted: 25-10-2021
import pwd, grp for p in pwd.getpwall(): print p, grp.getgrgid(p)
grp module is your friend. Look at
grp.getgrall() to get a list of all groups and their members.
Answered by: Oliver555 | Posted: 25-10-2021
import grp groups = grp.getgrall() for group in groups: for user in group: print user, group
Answered by: Dexter169 | Posted: 25-10-2021
getent passwd | cut -f1 -d: | while read name; do echo -n "$name " ; groups $name ; done
The python call to
grp.getgrall() only shows the local groups, unlike the call to getgrouplist c function which retruns all users, e.g. also users in sssd that is backed by an ldap but has enumeration turned off. (like in FreeIPA).
After searching for the easiest way to get all groups a users belongs to in python the best way I found was to actually call the getgrouplist c function:
#!/usr/bin/python import grp, pwd, os from ctypes import * from ctypes.util import find_library libc = cdll.LoadLibrary(find_library('libc')) getgrouplist = libc.getgrouplist # 50 groups should be enought? ngroups = 50 getgrouplist.argtypes = [c_char_p, c_uint, POINTER(c_uint * ngroups), POINTER(c_int)] getgrouplist.restype = c_int32 grouplist = (c_uint * ngroups)() ngrouplist = c_int(ngroups) user = pwd.getpwuid(2540485) ct = getgrouplist(user.pw_name, user.pw_gid, byref(grouplist), byref(ngrouplist)) # if 50 groups was not enough this will be -1, try again # luckily the last call put the correct number of groups in ngrouplist if ct < 0: getgrouplist.argtypes = [c_char_p, c_uint, POINTER(c_uint *int(ngrouplist.value)), POINTER(c_int)] grouplist = (c_uint * int(ngrouplist.value))() ct = getgrouplist(user.pw_name, user.pw_gid, byref(grouplist), byref(ngrouplist)) for i in xrange(0, ct): gid = grouplist[i] print grp.getgrgid(gid).gr_name
Getting a list of all users to run this function on similarly would require to figure out what c call is made by
getent passwd and call that in python.
a simple function which is capable to deal with the structure of any one of these files (/etc/passwd and /etc/group).
I believe that this code meets your needs, with Python built-in functions and no additional module:
Answered by: William760 | Posted: 25-10-2021
#!/usr/bin/python def read_and_parse(filename): """ Reads and parses lines from /etc/passwd and /etc/group. Parameters filename : str Full path for filename. """ data =  with open(filename, "r") as f: for line in f.readlines(): data.append(line.split(":")) data.sort() for item in data: print("- " + item) read_and_parse("/etc/group") read_and_parse("/etc/passwd")
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