Create a List that contain each Line of a File [duplicate]
I'm trying to open a file and create a list with each line read from the file.
i=0
List=[""]
for Line in inFile:
List[i]=Line.split(",")
i+=1
print List
But this sample code gives me an error because of the i+=1 saying that index is out of range.
What's my problem here? How can I write the code in order to increment my list with every new Line in the InFile?
Asked by: Alina911 | Posted: 28-01-2022
Answer 1
It's a lot easier than that:
List = open("filename.txt").readlines()
This returns a list of each line in the file.
Answered by: Ned509 | Posted: 01-03-2022Answer 2
I did it this way
lines_list = open('file.txt').read().splitlines()
Every line comes with its end of line characters (\n\r); this way the characters are removed.
Answered by: Justin677 | Posted: 01-03-2022Answer 3
my_list = [line.split(',') for line in open("filename.txt")]
Answer 4
Please read PEP8. You're swaying pretty far from python conventions.
If you want a list of lists of each line split by comma, I'd do this:
l = []
for line in in_file:
l.append(line.split(','))
You'll get a newline on each record. If you don't want that:
l = []
for line in in_file:
l.append(line.rstrip().split(','))
Answer 5
A file is almost a list of lines. You can trivially use it in a for loop.
myFile= open( "SomeFile.txt", "r" )
for x in myFile:
print x
myFile.close()
Or, if you want an actual list of lines, simply create a list from the file.
myFile= open( "SomeFile.txt", "r" )
myLines = list( myFile )
myFile.close()
print len(myLines), myLines
You can't do someList[i] to put a new item at the end of a list. You must do someList.append(i).
Also, never start a simple variable name with an uppercase letter. List confuses folks who know Python.
Also, never use a built-in name as a variable. list is an existing data type, and using it as a variable confuses folks who know Python.
Answer 6
f.readlines() returns a list that contains each line as an item in the list
if you want eachline to be split(",") you can use list comprehensions
[ list.split(",") for line in file ]
Answer 7
Assuming you also want to strip whitespace at beginning and end of each line, you can map the string strip function to the list returned by readlines:
map(str.strip, open('filename').readlines())
Answer 8
... Also If you want to get rid of \n
In case the items on your list are with \n and you want to get rid of them:
with open('your_file.txt') as f:
list= f.read().splitlines()
Answer 9
I am not sure about Python but most languages have push/append function for arrays.
Answered by: Aida862 | Posted: 01-03-2022Similar questions
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