How do I wrap a string in a file in Python?

How do I create a file-like object (same duck type as File) with the contents of a string?


Asked by: Ada776 | Posted: 24-09-2021






Answer 1

For Python 2.x, use the StringIO module. For example:

>>> from cStringIO import StringIO
>>> f = StringIO('foo')
>>> f.read()
'foo'

I use cStringIO (which is faster), but note that it doesn't accept Unicode strings that cannot be encoded as plain ASCII strings. (You can switch to StringIO by changing "from cStringIO" to "from StringIO".)

For Python 3.x, use the io module.

f = io.StringIO('foo')

Answered by: Chester426 | Posted: 25-10-2021



Answer 2

In Python 3.0:

import io

with io.StringIO() as f:
    f.write('abcdef')
    print('gh', file=f)
    f.seek(0)
    print(f.read())

The output is:

'abcdefgh'

Answered by: Sophia253 | Posted: 25-10-2021



Answer 3

This works for Python2.7 and Python3.x:

io.StringIO(u'foo')

Answered by: Andrew308 | Posted: 25-10-2021



Answer 4

If your file-like object is expected to contain bytes, the string should first be encoded as bytes, and then a BytesIO object can be used instead. In Python 3:

from io import BytesIO

string_repr_of_file = 'header\n byline\n body\n body\n end'
function_that_expects_bytes(BytesIO(bytes(string_repr_of_file,encoding='utf-8')))

Answered by: Aida710 | Posted: 25-10-2021



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