# How to calculate next Friday?

How can I calculate the date of the next Friday?

Asked by:

**Ryan600**| Posted: 27-01-2022

# Answer 1

A certain improvement on @taymon`s answer:

```
today = datetime.date.today()
friday = today + datetime.timedelta( (4-today.weekday()) % 7 )
```

4 is Friday's weekday (0 based, counting from Monday).

`( (4-today.weekday()) % 7)`

is the number of days till next friday (`%`

is always non-negative).

After seeing @ubuntu's answer, I should add two things:

1. I'm not sure if Friday=4 is universally true. Some people start their week on Sunday.

2. On Friday, this code returns the same day. To get the next, use `(3-today.weekday())%7+1`

. Just the old `x%n`

to `((x-1)%n)+1`

conversion.

**Darcy830**| Posted: 28-02-2022

# Answer 2

To start off, you'll need the `datetime`

library:

```
import datetime
```

Then you need a starting date; that is, today.

```
d = datetime.date.today()
```

Starting from there, you'll want to keep going forward until you reach Friday. The `date.weekday`

method represents Monday through Sunday as 0 through 6, so:

```
while d.weekday() != 4:
```

If the current day isn't Friday, you'll have to add a day, one at a time. To add an interval of time to a `date`

object, you use a `timedelta`

object.

```
d += datetime.timedelta(1)
```

Put it all together, and `d`

will ultimately contain a `date`

object representing next Friday. Note that if today is Friday, this code will produce today; you can tweak it if you need it to produce next Friday instead.

**Lyndon694**| Posted: 28-02-2022

# Answer 3

Here is how you could do it using dateutil:

```
import datetime as DT
import dateutil.relativedelta as REL
today = DT.date.today()
print(today)
# 2012-01-10
rd = REL.relativedelta(days=1, weekday=REL.FR)
next_friday = today + rd
print(next_friday)
# 2012-01-13
```

(The `days = 1`

argument ensures that the "next Friday" is not the same as `today`

in case `today`

happens to be a Friday.)

**Edgar707**| Posted: 28-02-2022

# Answer 4

I found this pendulum pretty useful. Just one line

```
>>> pendulum.now().next(pendulum.FRIDAY).strftime('%Y-%m-%d')
'2019-04-26'
```

Answered by: **Kellan786**| Posted: 28-02-2022

# Answer 5

You can calculate any next day dates using these this code below.

```
from datetime import datetime as dt
from datetime import timedelta
def get_weekday(day):
days = ["mon","tue","wed","thu","fri","sat","sun"]
return days.index(day) + 1
def get_next_dayofweek_datetime(date_time, dayofweek):
start_time_w = date_time.isoweekday()
target_w = get_weekday(dayofweek)
if start_time_w < target_w:
day_diff = target_w - start_time_w
else:
day_diff = 7 - (start_time_w - target_w)
return date_time + timedelta(days=day_diff)
def get_next_n_weekends_dates(date_time, weekday, n=2):
days_list = []
week_date_time = date_time
while n > 0:
week_date_time = get_next_dayofweek_datetime(week_date_time, weekday)
days_list.append(week_date_time)
n = n -1
return days_list
start_time = dt.strptime("2020-02-01 20:20:00", "%Y-%m-%d %H:%M:%S") # wednesday
print(get_next_dayofweek_datetime(start_time, "thu"))
print(get_next_dayofweek_datetime(start_time, "fri"))
print(get_next_dayofweek_datetime(start_time, "sat"))
print(get_next_dayofweek_datetime(start_time, "sun"))
print(get_next_dayofweek_datetime(start_time, "mon"))
print(get_next_dayofweek_datetime(start_time, "tue"))
print(get_next_dayofweek_datetime(start_time, "wed"))
print(get_next_dayofweek_datetime(start_time, "thu"))
print("get next two fridays or mote ")
print(get_next_n_weekends_dates(start_time, "fri", 2))
```

output:

```
2020-02-06 10:20:00
2020-02-07 10:20:00
2020-02-08 10:20:00
2020-02-02 10:20:00
2020-02-03 10:20:00
2020-02-04 10:20:00
2020-02-05 10:20:00
2020-02-06 10:20:00
get next two fridays or mote
[datetime.datetime(2020, 2, 7, 10, 20), datetime.datetime(2020, 2, 14, 10, 20)]
```

Answered by: **Blake649**| Posted: 28-02-2022

# Answer 6

Just for readability I would use strftime('%A') rather than weekday():

```
import datetime
d = datetime.date.today()
while d.strftime('%a') != 'Fri':
d += datetime.timedelta(1)
```

Answered by: **David914**| Posted: 28-02-2022

# Answer 7

```
import datetime
def next_fri_13(start_date):
next_friday = start_date + datetime.timedelta(((4 - today.weekday()) % 7))
while True:
if next_friday.day==13:
thirteen_friday = next_friday
break
else:
next_date = next_friday + datetime.timedelta(days=1)
next_friday = next_date + datetime.timedelta(((4 -next_date.weekday())% 7))
return thirteen_friday
r = next_fri_13(datetime.date(2020, 2, 11)) print(r)
```

Answered by: **Sophia740**| Posted: 28-02-2022

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